Mi vs SRH, IPL 2025: Mumbai Indians won the fourth consecutive win on the basis of Rohit Sharma’s explosive innings and defeated Sunrisers Hyderabad by 7 wickets. In the 41st match of IPL 2025, Mumbai Indians won the toss and invited Hyderabad to bat first. Hyderabad’s team was able to score only 143 runs after losing 8 wickets in 20 overs. On the basis of Rohit Sharma’s innings of 70 runs, Mumbai Indians lost only 3 wickets and scored 146 runs in 15.4 overs. Rohit faced 46 balls, with 3 sixes and 8 fours. Apart from this, Suryakumar Yadav played an explosive innings of 40 runs in 19 balls with the help of 5 fours and two sixes in 19 balls. For Mumbai, Ryan Ryan Ricelton 11, Will Jax 22 and Tilak Verma scored two not out. In bowling, Deepak Chahar for Mumbai took two, Bolt took 4, Bumrah and captain Hardik Pandya took one wicket each.
Klassen’s ‘class’ also could not win Hyderabad
Sunrisers Hyderabad did not start well. Travis head was out on the team score of two. After that the team got the second blow on the score of 9 as Ishaan Kishan. Then when the team’s score was 13 runs, Abhishek Sharma was dismissed for only 8 runs. The team suffered a fourth setback as Nitish Reddy. While the team’s score was only 35 runs, at that time Aniket Verma suffered a fifth shock. But after that wicketkeeper Klassen not only crossed his team by 100 runs, but also brought the respectable score to 143. Klassen scored 71 runs in 44 balls with the help of 9 fours and two sixes. For Hyderabad, Abhinav Manohar scored 43 runs in 37 balls with the help of 2 fours and 3 sixes.
Long jump in Mumbai’s points table
With a 7 -wicket win against Hyderabad, Mumbai Indians have also made a strong comeback in the points table. After winning 5 matches, Mumbai has reached third place with 10 points. This is Mumbai’s fifth and fourth consecutive win in IPL 2025.
